Consider a light ray travelling in air is incident into a medium of refractive index √2n The incident angle is twice that of refracting angle. Then, the angle of incidence will be:

Ray Optics and Optical Instruments | Refraction of Light and Laws of Refraction

Consider a light ray travelling in air is incident into a medium of refractive index √2n The incident angle is twice that of refracting angle. Then, the angle of incidence will be:

\(\tt sin^{-1} (\sqrt{n})\)

\(\large \tt cos^{-1} (\sqrt{\frac{n}{2}})\)

\(\tt sin^{-1} (\sqrt{2n})\)

\(\large \tt 2 cos^{-1} (\sqrt{\frac{n}{2}})\)

Solution : D
=> According to the law,
=> 1 x sin\(\tt \theta\) = \(\tt \sqrt{2n}\) x \(\tt sin(\frac{\theta}{2})\)
=> cos\(\tt \frac{\theta}{2}\) = \(\tt \sqrt{\frac{n}{2}}\)
=> \(\large \tt \theta = 2 cos^{-1} (\sqrt{\frac{n}{2}})\)